# 1. Assume the speed of vehicles along a stretch of I-10 has an approximately

1. Assume the speed of vehicles along a stretch of I-10 has an approximately
normal distribution with a mean of 71 mph and a standard deviation of 8 mph.
a. The current speed limit is 65 mph. What is the proportion of vehicles less than
or equal to the speed limit?
b. What proportion of the vehicles would be going less than 50 mph?
c. A new speed limit will be initiated such that approximately 10% of vehicles
will be over the speed limit. What is the new speed limit based on this criterion?
d. In what way do you think the actual distribution of speeds differs from a
normal distribution?
2. A group of students at a school takes a history test. The distribution is normal
with a mean of 25, and a standard deviation of 4. (a) Everyone who scores in
the top 30% of the distribution gets a certificate. What is the lowest score
someone can get and still earn a certificate? (b) The top 5% of the scores get to
compete in a statewide history contest. What is the lowest score someone can
get and still go onto compete with the rest of the state?
3. Use the normal distribution to approximate the binomial distribution and find
the probability of getting 15 to 18 heads out of 25 flips. Compare this to what
you get when you calculate the probability using the binomial distribution.
4. The patient recovery time from a particular surgical
procedure is normally distributed with a mean of 5.3 days and a standard deviation of 2.1 days.
What is the median recovery time?
a. 2.7
b. 5.3
c. 7.4
d. 2.1
5. Height and weight are two measurements used to track a child’s development. TheWorld Health Organization measures
child development by comparing the weights of children who are the same height and the same gender. In 2009, weights for
all 80 cm girls in the reference population had a mean μ = 10.2 kg and standard deviation σ = 0.8 kg. Weights are normally
distributed. X ~ N(10.2, 0.8). Calculate the z-scores that correspond to the following weights and interpret them.
a. 11 kg
b. 7.9 kg
c. 12.2 kg
6. In China, four-year-olds average three hours a day unsupervised. Most of the unsupervised children live in rural areas,
considered safe. Suppose that the standard deviation is 1.5 hours and the amount of time spent alone is normally distributed.
We randomly select one Chinese four-year-old living in a rural area.We are interested in the amount of time the child spends
alone per day.
a. In words, define the random variable X.
b. X ~ _____(_____,_____)
c. Find the probability that the child spends less than one hour per day unsupervised. Sketch the graph, and write the
probability statement.
d. What percent of the children spend over ten hours per day unsupervised?

e. Seventy percent of the children spend at least how long per day unsupervised?

There is no other information with this problem....the only other option I have is to do an extra credit problem in place of it....

Extra Credit: Facebook provides a variety of statistics on its Web site that detail the growth and popularity of the site.

On average, 28 percent of 18 to 34 year olds check their Facebook profiles before getting out of bed in the morning. Suppose

this percentage follows a normal distribution with a standard deviation of five percent.

a. Find the probability that the percent of 18 to 34-year-olds who check Facebook before getting out of bed in the

morning is at least 30.

b. Find the 95th percentile, and express it in a sentence.